Rubik's Cube PLL Corners
This page provides an interactive case guide after JavaScript loads; the list below covers every case.
Case recognition
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Has bar (back)
The two outlined stickers are on the B (back) face and match — bar is in position, just apply Aa.
U Align
Aa Formula
Recognize · bar at back
Look at the two outlined stickers — they're on the B (back) face and share the same color. The bar is already at the back.
Two outlined same-color stickers on the B face.
Bar at B = Aa's working position, anchor aligned, no U needed.
Just apply Aa to finish.
U Align
U check
Bar is already at B, no U adjustment needed.
U finish
After Aa, rotate U to align corners with side centers.
Aa · one step
bar@B → apply Aa (R' F R' B2 R F' R' B2 R2) → corners home.
Outline on B face, bar in position.
Two outlined stickers on B face share the same color.
Execute Aa directly.
R' F R' B2 R F' R' B2 R2
Aa holds the ULF anchor fixed and 3-cycles the other three. bar@B means those three cycling corners are arranged so Aa puts each one home in one step.
Aa
Execute Aa (R' F R' B2 R F' R' B2 R2).
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Has bar (needs U)
The two outlined stickers are on F/R/L (not B) — U the bar to B, then apply Aa.
U Align
Aa Formula
Recognize · bar not at back
Look at the two outlined stickers — they're on F (front), R (right), or L (left), not B.
Outline on F/R/L, no outline on B.
The system picks a U direction to bring the bar to B.
Once bar reaches B, it's identical to bar@b — apply Aa.
U Align
U adjust
The system chose a U direction to move the outlined bar from F/R/L to B.
U finish
After Aa, rotate U to align corners with side centers.
Aa · one step
U bar to B → apply Aa (R' F R' B2 R F' R' B2 R2) → home.
Outline has moved to B face.
Two outlined stickers on B face share the same color.
Once bar is at B, execute Aa directly.
R' F R' B2 R F' R' B2 R2
Aa holds the ULF anchor fixed and 3-cycles the other three. After U brings the bar to B, the arrangement is identical to bar@b, so Aa solves in one step.
Aa
Execute Aa (R' F R' B2 R F' R' B2 R2).
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No bar · Aa×2
No outline at all — all four faces mismatch. Apply Aa once and a bar always appears, then follow the bar flow.
U Align
Aa Formula
Recognize · no bar
Check all four faces — no outlined stickers anywhere. No face has two matching top corners.
No outline = no bar. All four faces have different colors.
No bar to find, no U adjustment — just apply Aa directly.
After one Aa, an outline always appears (bar emerges), then follow the bar flow. Worst case = two Aa's.
U Align
U adjust
Rotate U: after Aa creates a bar, move the outline to B.
U finish
After the second Aa, rotate U to align corners with side centers.
Aa · one formula, two roles
Apply Aa (R' F R' B2 R F' R' B2 R2). No bar → Aa creates one; bar@B → Aa solves.
Check if there's an outline: none → first Aa creates bar; present → second Aa solves.
No outline → Aa makes one appear; outline present → Aa puts corners home.
Execute Aa directly.
R' F R' B2 R F' R' B2 R2 — same formula, effect depends on whether a bar exists.
No-bar states are double-transpositions (two diagonal pairs swapped). Aa is a 3-cycle — applying a 3-cycle to a double-transposition always produces a bar state. This is a mathematical property of permutations, not luck. So: no bar → Aa → bar always appears → AUF to B → Aa solves.
Aa
Execute Aa (R' F R' B2 R F' R' B2 R2).
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No bar · E-perm
No outline at all — all four faces mismatch. Use E-perm to solve all four corners in one step, more direct than two Aa's.
U Align
E-perm Formula
Recognize · no bar (E-perm)
Check all four faces — no outlined stickers anywhere. No face has two matching top corners.
No outline = no bar. All four faces mismatch — this is the E-perm signal.
No bar to find; recognize this as a no-bar double-swap, apply E-perm directly.
E-perm swaps two diagonal pairs at once — more direct than two Aa's.
U Align
U adjust
The system picks a U direction to align corners for E-perm's working position.
U finish
After E-perm, rotate U to align corners with side centers.
E-perm · double-swap one-shot
No bar (double-swap) → apply E-perm; x' R U' R' D R U R' D' R U R' D R U' R' D' x solves in one step.
No outline on top — all four corners misplaced (double-swap).
No outline = no matter how you U, you can't form two adjacent matching corners.
After the system's U alignment, execute E-perm directly.
x' R U' R' D R U R' D' R U R' D R U' R' D' x
E-perm is itself a double-swap formula — it swaps two diagonal pairs simultaneously. The no-bar state is exactly a double-swap, so E-perm cancels it in one step, placing all four corners home.
E-perm
Execute E-perm (x' R U' R' D R U R' D' R U R' D R U' R' D' x).